Products
Rewards
from HOLOOLY

We are determined to provide the latest solutions related to all subjects FREE of charge!

Enjoy Limited offers, deals & Discounts by signing up to Holooly Rewards Program

HOLOOLY

HOLOOLY
TABLES

All the data tables that you may search for.

HOLOOLY
ARABIA

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

HOLOOLY
TEXTBOOKS

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

HOLOOLY
HELP DESK

Need Help? We got you covered.

## Q. 6.14

Given the information provided in Fig. 6.24:
a. Determine $R_3$.
b. Find the applied voltage E.
c. Find the source current $I_s$.
d. Find $I_2$.

## Verified Solution

a. Applying Eq. (6.1) gives

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\cdot \cdot \cdot +\frac{1}{R_N}$           (6.1)

$\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

Substituting gives            $\frac{1}{4\Omega }=\frac{1}{10\Omega }+\frac{1}{20\Omega }+\frac{1}{R_3}+\cdot \cdot \cdot +\frac{1}{R_N}$

so that                                $0.25S=0.1S+0.05S+\frac{1}{R_3}$

and                                      $0.25S=0.15S+\frac{1}{R_3}$

with                                     $\frac{1}{R_3}=0.1S$

and                                      $R_3=\frac{1}{0.1S}=10\Omega$

b. Using Ohm’s law gives

$E=V_1=I_1R_1=(4A)(10\Omega )=40V$

c.                                         $I_s=\frac{E}{R_T}=\frac{40V}{4\Omega }=10A$

d. Applying Ohm’s law gives

$I_2=\frac{V_2}{R_2}=\frac{E}{R_2}=\frac{40V}{20\Omega }=2A$