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## Q. 35.6

In Fig. 35-19a, what is closed-loop voltage gain and bandwidth? What is the output voltage at 250 kHz?

## Verified Solution

With Formula (35-8), $A_{V(CL)} =\frac{R_f}{R_1}+1$

$A_{V(CL)} =\frac{3.9 k\Omega}{100}+1=40$

Dividing the unity-gain frequency by the closed-loop voltage gain gives

$f_{2(CL)} =\frac{1MHz}{40}=25 kHz$

Figure 35-19b shows the ideal Bode plot of closed-loop voltage gain. The decibel equivalent of 40 is 32 dB. (Shortcut: $40 = 10 \times 2\times$  2 or 20 dB +6 dB + 6 dB = 32 dB.) Since the $A_{v(CL)}$ breaks at 25 kHz, it is down 20 dB at 250 kHz. This means that$A_{v(CL)}$ =12 dB at 250 kHz, which is equivalent to an ordinary voltage gain of 4. Therefore, the output voltage at 250 kHz is

$v_{out} = 4 (50 mV p-p) = 200 mV p-p$