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Replace the loading by an equivalent force and couple moment at point O.

Units Used:

kN = { 10 }^{ 3 } N

Given:

{ w }_{ 1 } = 15 \frac { kN }{ m }

{ w }_{ 2 } = 5 \frac { kN }{ m }

d = 9 m

Step-by-step

{ F }_{ R } = \frac { 1 }{ 2 } ({ w }_{ 1 }+{ w }_{ 2 })d

{ M }_{ RO } = { w }_{ 2 }d\frac { d }{ 2 } +\frac { 1 }{ 2 } \left( { w }_{ 1 }-{ w }_{ 2 } \right) d\frac { d }{ 3 }

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