## Question:

Replace the loading by an equivalent resultant force and couple moment acting at point $A$.

Units Used:

$kN$ = ${ 10 }^{ 3 }$ $N$

Given:

${ w }_{ 1 }$ = $600$ $\frac { N }{ m }$

${ w }_{ 2 }$ = $600$ $\frac { N }{ m }$

$a$ = $2.5$ $m$

$b$ = $2.5$ $m$

## Step-by-step

${ F }_{ R }$ = ${ w }_{ 1 }{ a-w }_{ 2 }b$$\quad \quad { F }_{ R }$ = $0$ $N$

${ M }_{ RA }$ = ${ w }_{ 1 }a\left( \frac { a+b }{ 2 } \right)$ $\quad \quad { M }_{ RA }$ = $3.75$ $kN.m$