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## Q. 3.6

The data sheet for a certain enhancement-type MOSFET reveals that $I_{D(on)} = 10 mA$ at $V_{GS} = −12 V$  and $V_{GS(th)}= −3 V$. Is this device p-channel or n-channel? Find the value of $I_D$, when $V_{GS} = −6 V$.

## Verified Solution

Given that
$I_{D(on)}=10 mA$;$V_{GS}=-12 V$ and $V_{GS(th)}=-3V$.
Since the value of $V_{GS}$ is negative for the enhancement-type MOSFET, this
indicated that the device is p-channel. Also $V_{GS(th)} = V_t$.
We know that the saturated drain current is given by
$I_D=K[V_{GS}-V_{GS(th)}]^2$
$I_{D(on)}=K[V_{GS}-V_{GS(th)}]^2$
or
$10=K[-12-(-3)]^2=81 K$
$K={10}/{81}={0.12 mA}/{V}$
Substituting this value of K and $V_{GS}$ (equal to −6) in the equation of $I_D$ above,
$I_D=0.12[-6-(-3)]^2=1.08 mA$ Ans.