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The sphere of weight W rests between the smooth inclined planes. Determine the reaactions at the supports.

Given:

W = 10 Ib

{ \theta }_{ 1 } = 105 deg

{\theta }_{ 2 } = 45 deg

Step-by-step

Initial guesses

{ N }_{ A } = 1 Ib\quad { N }_{ A } = 1 Ib

Given:

{ N }_{ B }\cos { \left( { \theta }_{ 1 }-90deg \right) } -{ N }_{ A }\cos { \left( { \theta }_{ 2 } \right) } = 0

{ N }_{ A }\sin { \left( { \theta }_{ 2 } \right) } -{ N }_{ B }\sin { \left( { \theta }_{ 1 }-90deg \right) } -W = 0

\left( \begin{matrix} { N }_{ A } \\ { N }_{ B } \end{matrix} \right) = Find({ N }_{ A },{ N }_{ B })\quad \quad \quad \left( \begin{matrix} { N }_{ A } \\ { N }_{ B } \end{matrix} \right) =\left( \begin{matrix} 19.3 \\ 14.1 \end{matrix} \right) Ib

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