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Using the voltage divider rule, determine the voltages V_1 and V_2 of Fig. 5.62.
Redrawing the network with the standard battery symbol results in the network in Fig. 5.63. Applying the voltage divider rule gives
V_1=\frac{R_1E}{R_1+R_2}=\frac{(4\Omega )(24V)}{4\Omega +2\Omega } =16VV_2=\frac{R_2E}{R_1+R_2}=\frac{(2\Omega )(24V)}{4\Omega +2\Omega } =8V
