What is the voltage gain in Fig. 33-24? The output voltage across the load resistor?
Chapter 33
Q. 33.8
Step-by-Step
Verified Solution
The ac collector resistance is
r_c = R_C \parallel R_L = (3.6 k\Omega \parallel 2.2 k\Omega) = 1.37 k\OmegaThe dc emitter current is approximately
I_E=\frac{1.8 V-0.7 V}{1K\Omega }=1.1 mAThe ac resistance of the emitter diode is
r^\prime _c=\frac{25 mV}{1.1 mA} =22.7 \OmegaThe voltage gain is
A_V=\frac{r_c}{r^\prime _c}=\frac{1.37 k\Omega}{22.7 \Omega}=60.35The output voltage is
v_{out} = A_Vv_{in} = (60.35)(100) \mu V = 6.035 mV