Contemporary Electronics: Fundamentals, Devices, Circuits, and Systems 1st. Edition by Frenzel, Louis | 9780073373805 | 007337380X | Holooly

Contemporary Electronics: Fundamentals, Devices, Circuits, and Systems [EXP-36259]

244 SOLVED PROBLEMS

Question: 18.8

A 10-H inductance L1 on an iron core produces 4 Wb of magnetic flux. Another coil L2 is on the same core. How much is k between L1 and L2?

Verified Answer:

Unity or 1. All coils on a common iron core have p...

Question: 20.4

A 200-μH coil has a Q of 40 at 0.5 MHz. Find Re.

Verified Answer:

R_e=\frac{X_L}{Q}=\frac{2\pi fL}{Q}

...

Question: 32.1

A 2N5457 has IDSS = 5 mA and gm0 = 5000 μS. What is the value of VGS(off)? What does gm equal when VGS = -1 V?

Verified Answer:

With Formula (32-10),

V_{GS(off)}=\frac{-2I_...

Question: 17.2

A 30-mA IR is in parallel with another branch current of 40 mA for IC. The applied voltage VA is 72 V. Calculate IT, ZEQ, and θI

Verified Answer:

This problem can be calculated in mA units for I a...

Question: 12.2

A 50-µA meter movement has an rM of 1000 Ω. What RS is needed to extend the range to 500 µA?

Verified Answer:

The shunt current

I_S

is 500 _ 50, ...

Question: 23.4

A certain amplifier has an input power of 1 W and an output power of 100 W. Calculate the dB power gain of the amplifier.

Verified Answer:

Use Formula (23-11):

N_{dB}=10 \log \frac{P...

Question: 25.3

A coaxial cable has an attenuation of 3.5 dB per 100 ft at 100 MHz. a. What is the attenuation of 60 ft of cable? b. How is attenuation affected if the frequency is raised to 300 MHz?

Verified Answer:

a. Attenuation per foot is 3.5/100 = 0.035 dB/ft, ...

Question: 18.7

A coil L1 produces 80 μWb of magnetic flux. Of this total flux, 60 μWb are linked with L2. How much is k between L1 and L2?

Verified Answer:

k=\frac{60 \mu Wb}{80\mu Wb}

[latex...

Question: 11.2

A coil with 4 A is to provide a magnetizing force of 600 A?t. How many turns are necessary?

Verified Answer:

N=\frac{A.t}{I}=\frac{600}{4} =150 turns[...

Question: 19.4

A coil with negligible resistance has 62.8 V across it with 0.01 A of current. How much is XL?

Verified Answer:

X_L=\frac{V_L}{I_L}=\frac{62.8V}{0.01 A}[/l...

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