Question 8.9: Formaldehyde (CH2O), which can be used to preserve biologica...
Formaldehyde (CH2O), which can be used to preserve biological specimens, is commonly sold as a 37% aqueous solution. Use formal charges to determine which skeletal arrangement of atoms shown here is the best choice for the Lewis structure of CH2O.
H–C–O–H H- \overset{\overset{O}{|} }{\underset{ }{C}} – H
Strategy Complete the Lewis structures for each of the CH2O skeletons shown and determine the formal charges on the atoms in each one.
Setup The completed Lewis structures for the skeletons shown are:
H- \overset{..}{C}- \overset{..}{O}- H
In the structure on the left, the formal charges are as follows:
Both H atoms: 1 valence e– – 1 associated e– (from single bond) = 0
C atom: 4 valence e– – 5 associated e– (two in the lone pair, one from the single bond, and two from the double bond) = -1
O atom: 6 valence e– – 5 associated e– (two from the lone pair, one from the single bond, and two from the double bond) = +1
\underset{Formal charges}{} \underset{0}{H} – \overset{..}{\underset{-1}{C} } = \overset{..}{\underset{+1}{O} }- \underset{0}{H}
In the structure on the right, the formal charges are as follows:
Both H atoms: 1 valence e– – 1 associated e– (from single bond) = 0
C atom: 4 valence e– – 4 associated e– (one from each single bond, and two from the double bond) = 0
O atom: 6 valence e– – 6 associated e– (four from the two lone pairs and two from the double bond) = 0
Formal charges all zero
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Of the two possible arrangements, the structure on the left has an O atom with a positive formal charge, which is inconsistent with oxygen’s high electronegativity. Therefore, the structure on the right, in which both H atoms are attached directly to the C atom and all atoms have a formal charge of zero, is the better choice for the Lewis structure of CH2O.