Question 8.12: Draw the Lewis structure of boron triiodide (BI3).

Draw the Lewis structure of boron triiodide (BI₃).

Strategy Follow the step-by-step procedure for drawing Lewis structures. The skeletal structure is

$I – \overset{\overset{I}{|} }{\underset{ }{B}} – I$

Setup There are a total of 24 valence electrons in BI₃ (three from the B and seven from each of the three I atoms). We subtract six electrons to account for the three bonds in the skeleton, leaving 18 electrons to distribute as three lone pairs on each I atom.

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