Question 8.4.1: Heat of Vaporization At what rate in kilowatts must heat be ......

Elementary Principles of Chemical Processes [1025236]

Heat of Vaporization
At what rate in kilowatts must heat be transferred to a liquid stream of methanol at its normal boiling point to generate 1500 g/min of saturated methanol vapor?

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From Table B.1 or using APEx functions Tb and Hv, Δ $\hat{H}_{v}$ = 35.3 kJ/mol at T $_{b}$ = 64.7°C. The energy balance with potential and kinetic energy changes neglected is

\begin{matrix}\dot{Q}=\Delta \dot{H} = \dot{n}\Delta \hat{H}_{v} \\\\ \left. \Large{\Downarrow} \right. \\\\ \dot{Q} = \begin{array}{c|c|c|c|c} 1500  g  CH_{3}OH &1  mol& 35.3  kJ &1  min &1  kW\\ \hline min &32.0  g  CH_{3}OH &mol &60  s &1  kJ/s\end{array} = \boxed{27.6  kW}\end{matrix}

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