Question 13.1: Geometric Quantities of a V-Belt Drive A V belt is to operat......

a. Through the use of Equation (13.11),

b=L-\pi\left(r_2+r_1\right)     (13.11)

b=L-\pi\left(r_1+r_2\right)=69.8-\pi(6+4)=38.38  in.

Equation (13.10) is therefore

c=\frac{1}{4}\left[b+\sqrt{b^2-8\left(r_2-r_1\right)^2}\right]       (13.10)

c=\frac{1}{8}\left[38.38+\sqrt{38.38^2-8(6-4)^2}\right]=19.09  in.

b. Applying Equation (13.7),

\phi=\pi-2 \alpha       (13.7)

\phi=\pi-2 \alpha=180^{\circ}-2 \sin ^{-1}\left(\frac{6-4}{19.09}\right)=168^{\circ}