Question 25.10: High- and Low-Spin Octahedral Complexes How many unpaired el...
High- and Low-Spin Octahedral Complexes
How many unpaired electrons are there in the complex ion [Co(NH_3)_5NO_2]^{2+}?
| Determining the Number of Unpaired Electrons in Octahedral Complexes | ||
| Begin by determining the charge and number of d electrons on the metal. | SOLUTION
The metal is Co^{3+} and has a d^{6} electronic configuration. |
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| Look at the spectrochemical series to determine whether the ligand is a strong-field or a weak-field ligand. | NH_3 and NO_2{}^- are both strong-field ligands, so Δ is relatively large. | |
| Decide if the complex is high- or low-spin and draw the electron configuration. | Strong-field ligands yield low-spin configurations.
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| Count the unpaired electrons. | This configuration has no unpaired electrons. | |
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