Calculate osmotic pressure for a solution containing a nonelectrolyte.
The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C_{7}H_{5}N_{3}O_{6} (227.10 g/mol), is soluble in benzene (C_{6}H_{6}). Calculate the osmotic pressure generated when 14.3 g of TNT is dissolved in 242 mL of a benzene solution at 298 K.
You are asked to calculate osmotic pressure for a solution.
You are given the mass of solute in the solution, the volume of the solution, and the temperature of the solution.
14.3 g TNT × \frac{1\text{ mol TNT}}{227.1\text{ g}} = 0.0630 mol TNT
\frac{0.0630\text{ mol TNT}}{0.242\text{ L}} = 0.260 M
The van’t Hoff factor (i) for the solute is 1 because it is a nonelectrolyte.
∏ = cRTi = (0.260 M)(0.082057 L · atm/K · mol)(298 K)(1) = 6.36 atm