Determine α and β for the transistor of Example 3.1 if leakage currents (flow due to holes) are negligible and the described charge flow is constant.
If we assume I_{CBO} = I_{CEO} = 0, then
α = \frac{i_C}{i_E} = \frac{i_E – i_B}{i_E} = \frac{1.602 – 0.016}{1.602} = 0.99and β = \frac{i_C}{i_B} = \frac{i_E – i_B}{i_B} = \frac{1.602 – 0.016}{0.016} = 99.125