Write formulas for the following compounds:
(a) Potassium hypochlorite (b) Silver(I) chromate (c) Iron(III) carbonate
(a) KClO Potassium forms only the K^{+} ion, so only one ClO^{-} is needed.
(b) Ag_{2}CrO_{4} The polyatomic chromate ion has a -2 charge, so two Ag^{+} ions are needed.
(c) Fe_{2}(CO_{3})_{3} Iron(III) has a +3 charge and the polyatomic carbonate ion has a -2 charge, so there must be two iron ions and three carbonate ions. The polyatomic carbonate ion is set off in parentheses to indicate that there are three of them.