Question 2.5: What is the voltage across the 6 Ω resistor?...

What is the voltage across the 6 Ω resistor?

2.5
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The right-hand side of the circuit, consisting of the two 10 Ω resistors and the 5 Ω resistor, is irrelevant insofar as the determination of voltage across the 6 Ω resistor is concerned.
Parallel combination of the two 8 Ω resistors results in an equivalent resistance of 4 Ω as follows:

R_{8  Ω/8  Ω}=\frac{(8  Ω).(8  Ω)}{8  Ω+8  Ω}

Using voltage division, the voltage across the 6 Ω resistor would be as follows:

V_{6  Ω}=(10  V).\left\lgroup\frac{6  Ω}{4  Ω+6  Ω}\right\rgroup

 

=6  V

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