Question 3.9: A vertical triangular area with vertex downward, as shown in......
A vertical triangular area with vertex downward, as shown in Figure 3.21, is immersed in liquid with its base in the free surface. Its altitude h is equal to its base. Find the depth of centre of pressure.
Step-by-Step
From Eq. (3.11), we have
y_{CP}=\frac{I_{o} }{Aȳ}
From Figure 3.17(b), we get
y_{CP}=\frac{hh^{3} }{12}\frac{1}{(1/2)h^{2} (h/3)}=\frac{h^{4} }{2h^{3} }
Therefore, y_{CP}=\frac{h }{2}
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