Question 3.3: Write the primitive admittance matrix of the network of Figu......
Write the primitive admittance matrix of the network of Figure 3.8b.
Step-by-Step
The matrix is written by simply examining the figure. There are no mutual couplings between the elements. The required matrix is
The top and left-side identifications of the elements between nodes are helpful in the formation of the matrix. It is a diagonal matrix. If there are mutual couplings between elements of the network, the appropriate off-diagonal elements in the matrix are populated.
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | |
| 0–1 | 0–2 | 0–3 | 0–4 | 1–2 | 1–3 | 1–4 | 2–4 | 3–4 | |
| 0–1 | y_{10} | ||||||||
| 0–2 | y_{20} | ||||||||
| 0–3 | y_{30} | ||||||||
| 0–4 | y_{40} | ||||||||
| 1–2 | y_{12} | ||||||||
| 1–3 | y_{13} | ||||||||
| 1–4 | y_{14} | ||||||||
| 2–4 | y_{24} | ||||||||
| 3–4 | y_{34} |
Related Answered Questions
Question: 3.8
Verified Answer:
The primitive impedance or admittance matrices can...
Question: 3.7
Verified Answer:
The primitive impedance matrix is
\overset{...
Question: 3.6
Verified Answer:
From Example 3.1,
\left|\begin{matrix} 1-j...
Question: 3.4
Verified Answer:
The bus incidence matrix is formed from the graph ...
Question: 3.2
Verified Answer:
From Equation 3.20 we note that the zero elements ...
Question: 3.1
Verified Answer:
The bus admittance matrix is formed by inspection....