Find the current through 100 Ω resistance in the circuit given below.
(a) 9.8 A (b) 10.5 A (c) 10 A (d) 5 A
Applying nodal analysis KCL at node 1, we get
\begin{gathered} \frac{50}{4}-\frac{10}{4}+\frac{V}{100}=0 \\ \frac{40}{4}+\frac{V}{100}=0 \end{gathered}
\begin{gathered} 10+\frac{V}{100}=0 \Rightarrow V=1000 \\ I=\frac{V}{100}=\frac{1000}{100}=10 A \end{gathered}