Question 7.139: Determine the internal normal force, shear force, and the mo...

For 0^{\circ} \leq \theta \leq 180^{\circ}:

V=150 \sin \theta-200 \cos \theta

N=150 \cos \theta+200 \sin \theta

M=150 \cos \theta+200 \sin \theta-150

At section B, \theta=180^{\circ}, thus

V_B=200  \mathrm{lb}

N_B=-150  \mathrm{lb}

M_B=-300  \mathrm{lb} \cdot \mathrm{ft}

For 0 \leq y \leq 2  \mathrm{ft}:

+↑ \Sigma F_y=0 ; \quad N=-150  \mathrm{lb}

M=-300-200  y