Question E.11: Problems with Equations Find the density (in g/ cm^3) of a m...

Problems with Equations
Find the density (in \ g/ cm^3) of a metal cylinder with a mass (m) of 8.3 g, a length (l) of 1.94 cm, and a radius (r) of 0.55 cm. For a cylinder, V = \pi r^2l.

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SORT Begin by sorting the information into given and find.

GIVEN: m = 8.3 g
l = 1.94 cm
r = 0.55 cm
FIND: d in g / cm^3

STRATEGIZE Write a conceptual plan for the problem. Focus on the equation(s). The conceptual plan shows how the equation takes you from the given quantity (or quantities) to the find quantity. The conceptual plan may have several parts, involving other equations or required conversions. In these examples, you use the geometrical relationships given in the problem statements as well as the definition of density, d = m / V, which you learned in this chapter.

RELATIONSHIPS USED

V=\pi r^2l

d=\frac{m}{V}

SOLVE Follow the conceptual plan. Solve the equation(s) for the find quantity (if it is not solved already). Gather each of the quantities that must go into the equation in the correct units. (Convert to the correct units if necessary.) Substitute the numerical values and their units into the equation(s) and calculate the answer. Round the answer to the correct number of significant figures.

SOLUTION

V= \pi r^2 l

=\pi(0.55 \ cm)^2(1.94 \ cm)

= 1.\underline{8}436 \ cm^3

d=\frac{m}{V}

=\frac{8.3 \ g}{1.\underline{8}436 \ cm^3}= 4.50195 \ g /cm^3

4.50195 g/cm³=4.5 g/cm³

CHECK Check your answer. Are the units correct? Does the answer make sense?

The units (g/cm^3) are correct. The magnitude of the answer seems correct for one of the lighter metals (see Table E.4).

TABLE E.4  The Density of Some Common Substances at 20 °C

Substance Density (g /cm3)
Charcoal (from oak) 0.57
Ethanol 0.789
Ice 0.917 (at 0 °C)
Water 1.00 (at 4 °C)
Sugar (sucrose) 1.58
Table salt (sodium chloride) 2.16
Glass 2.6
Aluminum 2.70
Titanium 4.51
Iron 7.86
Copper 8.96
Lead 11.4
Mercury 13.55
Gold 19.3
Platinum 21.4

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