Question 9.9: A potassium iodide solution may be used in a diet that is lo......
A potassium iodide solution may be used in a diet that is low in iodine. A KI solution is prepared by dissolving 5.0 g of KI in enough water to give a final volume of 250 mL. What is the mass/volume percent (m/v) of KI in the solution?
STEP 1 State the given and needed quantities.
Table 1
STEP 2 Write the concentration expression.
Mass/volume percent (m/v)= \frac{mass \space of \space solute}{volume \space of \space solution} \times 100 \%
STEP 3 Substitute solute and solution quantities into the expression and calculate.
Mass/volume percent (m/v)= \frac{\overset{Two \space SFs}{5.0 \space g \space KI} }{\underset{Two \space SFs}{250 \space mL \space solution} } \times 100 \% =2.0 \% \space \underset{Two \space SFs}{ (m/v) \space KI \space solution}
Table 1 :
| ANALYZE THE PROBLEM |
Given | Need | Connect |
| 5.0 g of KI solute, 250 mL of KI solution |
mass/volume percent (v/v) |
\frac{mass \space of \space solute}{ volume \space of \space solution} \times 100 \% |