Question 14.8: Selecting a Monetary Bill A box contains five $1 bills, thre......

Selecting a Monetary Bill

A box contains five $1 bills, three $5 bills, and two $10 bills. A person selects a bill at random. What is the expected value of the bill? Perform the experiment 25 times.

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Step 1 List all possible outcomes. They are $1,$5\$ 1, \$ 5, and $10\$ 10.

Step 2 Assign the probabilities to each outcome:

P($1)=510P($5)=310P($10)=210P(\$ 1)=\frac{5}{10} \quad P(\$ 5)=\frac{3}{10} \quad P(\$ 10)=\frac{2}{10}

Step 3 Set up a correspondence between the random numbers and the outcomes. Use random numbers 1 through 5 to represent a $1\$ 1 bill being selected, 6 through 8 to represent a $5\$ 5 bill being selected, and 9 and 0 to represent a $10\$ 10 bill being selected.

Step 4 Select 25 random numbers and tally the results.

Number Results ($)458291,1,5,1,10256461,1,5,1,59180310,1,5,10,1840605,1,10,5,109694310,5,10,1,1\begin{array}{|l|l|}\hline \text{Number }& \text{Results }(\$) \\\hline 45829 & 1,1,5,1,10 \\25646 & 1,1,5,1,5 \\91803 & 10,1,5,10,1 \\84060 & 5,1,10,5,10 \\96943 & 10,5,10,1,1 \\\hline\end{array}

Step 5 Compute the average:

Xˉ=ΣXn=$1+$1+$5++$125=$11625=$4.64\bar{X}=\frac{\Sigma X}{n}=\frac{\$ 1+\$ 1+\$ 5+\cdots+\$ 1}{25}=\frac{\$ 116}{25}=\$ 4.64

Hence, the average (expected value) is $4.64\$ 4.64.

Recall that using the expected value formula E(X)=Σ[XP(X)]E(X)=\Sigma[X \cdot P(X)] gives a theoretical average of

E(X)=Σ[XP(X)]=(0.5)($1)+(0.3)($5)+(0.2)($10)=$4.00E(X)=\Sigma[X \cdot P(X)]=(0.5)(\$ 1)+(0.3)(\$ 5)+(0.2)(\$ 10)=\$ 4.00

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