A wideband operational amplifier has a slew rate of 15 V/μs. If the amplifier is used in a circuit with a voltage gain of 20 and a perfect step input of 100 mV is applied to its input, determine the time taken for the output to change level.
The output voltage change will be 20 × 100 = 2,000 mV (or 2 V). Re-arranging the formula for slew rate gives:
\Delta t = \frac{\Delta V_{OUT}}{\text{Slew rate}} = \frac{2 V}{15 V/\mu s} = 0.133 \mu s