Plot the output waveform of the circuit shown in Fig. 3.56 if the initial condition across C_{1} is zero.
As V_{in} rises from zero, attempting to place positive charge on the left plate of C_{1} and hence draw negative charge from D_{1}, the diode turns off. As a result,C_{1} directly transfers the input change to the output for the entire positive half cycle. After t = t_{1}, the input tends to push negative charge into C_{1}, turning D_{1} on and forcing V_{out} = 0. Thus, the voltage across C_{1} remains equal to V_{in} until t = t_{2}, at which point the direction of the current through C_{1} and D_{1} must change, turning D_{1} off. Now, C_{1} carries a voltage equal to V_{p} and transfers the input change to the output; i.e., the output tracks the input but with a level shift of +V_{p}, reaching a peak value of +2V_{p}.