Question 10.SP.10: A boost converter with continuous inductor current is fed fr......

Schaum’s Outline of Electronic Devices and Circuits [1089587]

A boost converter with continuous inductor current is fed from a 12-V source with a 60 percent duty cycle while supplying a power of 60 W to the connected load. Determine (a) the output voltage, (b) the load resistance, and (c) the load current.

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(a) By (10.7),
$G_{V} = {\frac{V_{2}}{V_{1}}} = {\frac{1}{1 – D}}$ (10.7)
$V_{2} = {\frac{V_{1}}{1 – D}} = {\frac{12}{1.06}} = 30\,\mathrm{V}$

(b) Based on (1.23),
$P_{\mathrm{dc}} = {\frac{V_{\mathrm{dc}}^{2}}{R}}$ (1.23)
$R_{L} = {\frac{V_{2}^{2}}{P_{o}}} = {\frac{(30)^{2}}{60}} = 15\,\Omega$

(c) By Ohm’s law,

I_{2} = {\frac{V_{2}}{R_{L}}} = {\frac{30}{15}} = 2\,\mathrm{A}

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