Question 8.4: Predict the shape and the H–O–H bond angles for a hydronium ......

Predict the shape and the H–O–H bond angles for a hydronium ion, H_{3}O^{+}.

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The Lewis formula for a H_{3}O^{+} ion is

\begin{bmatrix} H -\overset{..}{O}- H \\\overset{|}{H} \end{bmatrix} ^{\oplus }

There are three hydrogen ligands and one lone pair attached to the central oxygen atom. Thus, it belongs to the class AX_{3}E. We see from Table 8.2 that it has a trigonal pyramidal shape. The H–O–H bond angles for a H_{3}O^{+} ion will be somewhat less than that of an ideal tetrahedron and so we predict that the angle is <109.5°.

TABLE 8.2 Molecular shapes. the white spheres represent the central atom, the red spheres represent ligands, and the green lobes represent lone pairs.
Molecular class Ideal shape Examples Molecular class Ideal shape Examples
 AX_{2} CO_{2},\ HCN,\ BeCl_{2}  AX_{4}E  SF_{4},\ XeO_{2}F_{2},\ IF^{+}_{4}, IO_{2}F^{–}_{2}
 AX_{3}  SO_{3},\ BF_{3},\ NO_{3}^{–},\ CO_{3}^{2–}  AX_{3}E_{2}  CIF_{3},\ BrF_{3}
 AX_{2}E  SO_{2},\ O_{3},\ PbX_{2},\ SnX_{2} (where X is
a halogen)
 AX_{2}E_{3}  XeF_{2},\ I^{–}_{3},\ IF^{–}_{2}
 AX_{4}  SiH_{4},\ CH_{4},\ SO_{4}^{2–},\ ClO_{4}^{–},\ PO^{3-}_{4},\ XeO_{4}  AX_{6}  SF_{6},\ IOF_{5}
 AX_{3}E  NH_{3},\ PF_{3},\ AsCl_{3}, ClO^{–}_{3},\ H_{3}O^{+},\ XeO_{3}  AX_{5}E  IF_{5},\ TeF_{5}^{–},\ XeOF_{4}
 AX_{2}E_{2}  H_{2}O,\ OF_{2},\ SF_{2}  AX_{4}E_{2}  XeF_{4}, ICI_{4}^{-}
 AX_{5}  PCl_{5},\ AsF_{5},\ SOF_{4}

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