Question 8.7: Predict the shape of the carbonate ion, CO3^2–....

Predict the shape of the carbonate ion, CO_{3}^{2–}.

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There are three equivalent resonance forms of a CO_{3}^{2–} ion:

\begin{matrix} ^{.^{.}}O^{^{.}.} \\ _{_{\diagup }} \overset{||}{C}_{_{\diagdown }} \\ ^{\circleddash }:\overset{.\ }{\underset{..}{O}}. \qquad .\overset{\ .}{\underset{..}{O}} :^{\circleddash } \end{matrix} \longleftrightarrow \begin{matrix} \ \ \ :\overset{..}{O}:^{\ominus } \\ _{_{^\diagup \diagup }}\overset{|}{C}_{_{\diagdown }} \\ \ \ \ :\underset{..}{O} \qquad .\overset{\ .}{\underset{..}{O}}: ^{\circleddash } \end{matrix} \longleftrightarrow \begin{matrix} :\overset{..}{O}:^{\circleddash } \\ _{_{\diagup }}\overset{|}{C} _{_{\diagdown ^\diagdown }} \\ ^{\circleddash }:\overset{.\ }{\underset{..}{O}}. \qquad \underset{..}{O}: \ \ \ \ \ \end{matrix}

The three equivalent resonance forms tell us that all three C–O bonds in a CO_{3}^{2–} ion are equivalent. In each resonance form there are three groups of electrons and no lone pairs around the central carbon atom. Thus, a CO_{3}^{2–} ion is of the class AX_3. We predict that a carbonate ion is trigonal planar with O–C–O bond angles of 120°. This prediction is in agreement with experimental results. The equivalence of the three C–O bonds in a CO_{3}^{2–} ion makes the three O–C–O bond angles equivalent (120°). 

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