Question 14.11: Calculate the energy as heat required to raise the temperatu......

Calculate the energy as heat required to raise the temperature of 150 kg of water (40 gallons, the volume of a typical home water heater in the U.S.) from 18°C to 60°C, assuming no loss of energy to the surroundings.

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The energy in the form of heat required can be calculated from Equation 14.30:

q_{P}=\Delta H=nC_{P}\Delta T          (14.30)

q_{P}=nC_{P}\Delta T \\ = (150\ kg)\left(\frac{1000\ g}{1\ kg} \right) \left(\frac{1\ mol}{18.016\ g} \right) (75.3\ J·mol^{–1}·K^{–1})(333  –  291)K \\= 2.6 × 10^{7}\ J = 26\ MJ

where 1\ MJ = 1\ megajoule = 1 × 10^{6}\ J. If natural gas provides the heating energy at a cost of about $1.50 per 100 MJ, it costs about 40 cents to heat 40 gallons of water from 18°C to 60°C, assuming that all the energy transferred as heat goes into the water. In practice, only about half the energy transferred as heat is absorbed by the water; the remainder is lost to the surroundings, so the actual cost is about 80 cents.

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