Question 23.9: Calculate the values of ΔG°rxn and K at 25°C for the equatio......

Calculate the values of ΔG^{\circ}_{rxn} and K at 25°C for the equation

PCl_{3}(g) + Cl_{2}(g) ⇋ PCl_{5}(g)
Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

Application of Equation 23.26 to this equation yields

ΔG^{\circ}_{rxn} = yΔG^{\circ}_{f}[Y] – zΔG^{\circ}_{f}[Z] – aΔG^{\circ}_{f}[A]-bΔG^{\circ}_{f}[B]                   (23.26)

ΔG^{\circ}_{rxn} = ΔG^{\circ}_{f}[PCl_{5}(g)] – ΔG^{\circ}_{f}[PCl_{3}(g)] – ΔG^{\circ}_{f}[Cl_{2}(g)]

The data from Table 23.1 yield

ΔG^{\circ}_{rxn}=(1)(–305.0\ kJ·mol^{–1}) – (1)(–267.8\ kJ·mol^{–1}) – (1)(0\ kJ·mol^{–1}) \\= –37.2\ kJ·mol^{–1}

The negative value of ΔG^{\circ}_{rxn} tells us that the reaction between PCl_{3}(g) and Cl_{2}(g) to produce PCl_{5}(g) is a spontaneous process under standard conditions at 25°C. The value of the equilibrium constant, K, for the reaction as described by the above equation is calculated using Equation 23.19:

ΔG^{\circ}_{rxn} = –RT\ ln\ K                  (23.19)

ln\ K = –\frac{ΔG^{\circ}_{rxn}}{RT} =-\frac{–37.2 × 10^3\ J·mol^{–1}}{(8.3145\ J·K^{–1}·mol^{–1})(298\ K)} =15.0

Thus,

K = e^{15.0} = 3 × 10^6
TABLE 23.1 Standard molar entropies (S°), enthalpies of formation (\Delta H^{\circ}_{f} ), and Gibbs energies of formation (\Delta G^{\circ}_{f} ) of various substances at 25°C and one bar (see also Appendix D)*
Substance S^{\circ}/J\cdot K^{−1}\cdot mol^{−1} \Delta H^{\circ}_{f}/kJ\cdot mol^{-1} \Delta G^{\circ}_{f}/kJ\cdot mol^{-1} Substance S^{\circ}/J\cdot K^{−1}\cdot mol^{−1} \Delta H^{\circ}_{f}/kJ\cdot mol^{-1} \Delta G^{\circ}_{f}/kJ\cdot mol^{-1}
Ag(s) 42.6 0 0 H_{2}O_{2}(l) 109.6 –187.8 –120.4
AgCl(s) 96.3 –127.0 –109.8 H_{2}S(g) 205.8 –20.6 –33.4
C(s,\ diamond) 2.4 1.9 2.9 N(g) 153.3 472.7 455.5
C(s,\ graphite) 5.7 0 0 N_2(g) 191.6 0 0
CH_{4}(g) 186.3 –74.6 –50.5 NH_{3}(g) 192.8 –45.9 –16.4
C_{2}H_{2}(g) 200.9 227.4 209.9 N_{2}H_{4}(l ) 121.2 50.6 149.3
C_{2}H_{4}(g) 219.3 52.4 68.4 NO(g) 210.8 91.3 87.6
C_{6}H_{6}(l) 173.4 49.1 124.5 NO_{2}(g) 240.1 33.2 51.3
CH_{3}OH(l ) 126.8 –239.2 –166.6 N_{2}O(g) 220.0 81.6 103.7
CH_{3}Cl(g) 234.6 –81.9 –58.4 N_{2}O_{4}(g) 304.4 11.1 99.8
CH_{3}Cl(l ) 145.3 –102 –51.5 N_{2}O_{5}(s) 178.2 –43.1 113.9
CH_{2}Cl_{2}(g) 270.2 –95.4 –68.8 Na(g) 153.7 107.5 77.0
CH_{2}Cl_{2}(l ) 177.8 –124.2 –70.0 Na(s) 51.3 0 0
CHCl_{3}(g) 295.7 –102.7 6.0 O(g) 161.1 249.2 231.7
CHCl_{3}(l) 201.7 –134.1 –73.7 O_{2}(g) 205.2 0 0
CO(g) 197.7 –110.5 –137.2 P(s, white) 41.1 0 0
CO_{2}(g) 213.8 –393.5 –394.4 P(s, red) 22.8 –17.6 –12.1
Cl(g) 165.2 121.3 105.3 PCl_3(g) 311.8 –287.0 –267.8
Cl_{2}(g) 223.1 0 0 PCl_5(g) 364.6 –374.9 –305.0
H(g) 114.7 218.0 203.3 S(s, rhombic) 28.5 0 0
H_{2}(g) 130.7 0 0 S(s, monoclinic) 32.6 0.3 0.1
H_{2}O(g) 188.8 –241.8 –228.6 SO_{2}(g) 248.2 –296.8 –300.1
H_{2}O(l) 70.0 –285.8 –237.1 SO_{3}(g) 256.8 –395.7 –371.1
*Most data from CRC Handbook of Chemistry and Physics, 87th Online Edition, 2006–2007.

Related Answered Questions