Question 2.SA.5: Use current division to determine the value of current I1 in......

Use current division to determine the value of current I_1 in the circuit below:

2.SA.5.1
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We must determine the value of source current I, first. In order to determine the value of current I flowing through the source and the two 5 Ω resistors, we must consolidate all resistors into an equivalent resistance R_{EQ} and then apply Ohm’s law.

R_{EQ}=5  Ω  + \left\lgroup\frac{(10  Ω)⋅(10  Ω)}{(10  Ω)+(10  Ω)}\right\rgroup + 5  Ω =5  Ω +5  Ω=15 Ω

I=\frac{V}{R_{EQ}}=\frac{12  V}{15  Ω}=0.8  A

Apply current division formula in the form of Eq. 2.7:

I_R= \left\lgroup\frac{R_{parallel}}{R_{total}}\right\rgroup⋅I       (2.7)

I_{10  Ω}=I_1=\left\lgroup\frac{R_{parallel}}{R_{total}}\right\rgroup⋅I =\left\lgroup\frac{10  Ω}{10  Ω+10  Ω}\right\rgroup⋅(0.8  A)=0.4  A

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