Question 17.PE.MCQ.10: A three-stage amplifier with identical stages has an overall......

(a) The lower cut-off frequency (f_{Ln}) for “n” identical non-interactive stage amplifiers is

f_{Ln}=\frac{f_{L}}{\sqrt{2^{1 / n}-1}}

Given that n = 3 and f_{Ln} = 10 Hz. Therefore,

f_{L}=10 \times \sqrt{0.257}=5 Hz

The upper cut-off frequency (f_{Hn} ) for “n” identical non-interactive stage amplifiers is

f_{ H n}=f_{ H } \sqrt{2^{1 / n}-1}

Given that f_{Hn} = 10 kHz and n = 3. Therefore,

f_{ H }=\frac{10,000}{\sqrt{0.257}}=19610 \,Hz

Therefore, the bandwidth is

19610 − 5 = 19605 Hz