In neutron scattering experiments, neutrons can be thought of as hard objects consisting of three quarks that are roughly spherical in shape. Suppose that a high-speed neutron of radius r scatters off of an oxygen nucleus of radius R and that the differential scattering cross section for this reaction is dσ/dΩ = (r + R)^2/4. What is the total scattering cross section σ_s for the neutron?
The total scattering cross section σ is simply the differential scattering cross section dσ/dΩ integrated over all solid angles between 0 and 2π, or σ_s = \int_{0}^{2\pi}{d\sigma/d\Omega d\Omega } . Performing the required integration yields σ_s = π(r + R)^2. So, in this case, the total cross section is just the area of the circle where the neutron and the oxygen nucleus overlap, and the radius of this circle is R′ = r + R.