The PDF for a particular nuclear reaction is given by the statistical probability distribution P(x) = 3e^{−3t}, where t is the time in seconds. Assuming that the process described by the PDF starts at t = 0, what is its corresponding CDF?
Its CDF is given by CDF = \int _{0}^{1}P(t)dt = \int _{0}^{1}3e^{-3t} dt = 1 – e^{-3t}.