Question 5.12: The length and diameter of an air-cored solenoid are 20 cm a......
The length and diameter of an air-cored solenoid are 20 cm and 4 cm, respectively. This solenoid is wound with 600 turns of copper wire and the coil carries a current of 4 A. Calculate the inductance and energy stored in the inductor.
Step-by-Step
Area of solenoid is calculated as,
A=\pi r^{2}=\pi\times\left({\frac{4\times10^{-2}}{2}}\right)^{2}=1.26\times10^{-3}\,\mathrm{m}^{2} (5.176)
The inductance is,
L={\frac{N^{2}\mu A}{l}}={\frac{600^{2}\times4\pi\times10^{-7}\times1\times1.26\times10^{-3}}{0.2}}=2.85~{\mathrm{mH}} (5.177)
The energy stored is calculated as,
w={\frac{1}{2}}L{i}^{2}={\frac{1}{2}}\times2.85\times10^{-3}\times4^{2}=22.8~{\mathrm{mJ}} (5.178)
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