Question 5.14: A circuit with resistance, inductance and capacitance is sho......
A circuit with resistance, inductance and capacitance is shown in Fig. 5.30. Calculate the source current and energy stored by the inductor and capacitor under DC condition.
Under DC condition, the inductor is short circuited and the capacitor is open circuited. In this case, the circuit is shown in Fig. 5.31. The equivalent circuit resistance is,
R_{\mathrm{eq}}=4+{\frac{3\times(5+1)}{3+6}}=6\,\Omega (5.219)
The source current is,
i={\frac{30}{6}}=5\,\mathbf{A} (5.220)
The branch currents are,
i_{1}=5\frac{6}{6+3}=3.33\,\mathrm{A} (5.221)
i_{1\Omega}=5-3.33=1.67\,\mathrm{A} (5.222)
The voltage drop across the open circuit is,
\nu_{c}=1.67\times1=1.67\mathrm{~V} (5.223)
The energies stored by the inductor and capacitor are,
w_{l}=\frac{1}{2}\times2\times3.33^{2}=11.09\;\mathrm{J} (5.224)
w_{c}=\frac{1}{2}\times3\times1.67^{2}=4.18\,\mathrm{J} (5.225)
