Question 11.SP.14: A 120-V ac voltage is applied across a 20-Ω resistive load (......
A 120-V ac voltage is applied across a 20-Ω resistive load (Fig. 11-25). Find values of I, V_{M}, V_{p-p}, V_{av}, I_{M}, I_{p-p}, I_{av}, and P.
Step-by-Step
By Ohm’s law,
I=\frac{V}{R_{L}}=\frac{120}{20}=6\ AUse Table 11-1 to calculate voltage and current values.
V_{M} = 1.414 V = 1.414(120) = 169.7 V
V_{p-p} = 2 V_{M} = 2(169.7) = 339.4 V
V_{av} = 0.637\ V_{M} = 0.637(169.7) = 108.3 V
I_{M} = 1.414 I = 1.414(6) = 8.5 A
I_{p-p} = 2 I_{M} = 2(8.5) = 17.0 A
I_{av} = 0.637 I_{M} = 0.637(8.5) = 5.4 A
P = I^{2}R_{L} = 6²(20) = 720 W
or P=\frac{V^{2}}{R_{L}}=\frac{120^{2}}{20}=720\ W or P=VI=120(6)=720\ W
| Table 11-1 Conversion Table for AC Sine Wave Voltage and Current | ||
| Multiply the Value
|
By
|
To Get the Value
|
| Peak | 2 | Peak-to-peak |
| Peak-to-peak | 0.5 | Peak |
| Peak | 0.637 | Average |
| Average | 1.570 | Peak |
| Peak | 0.707 | RMS (effective) |
| RMS (effective) | 1.414 | Peak |
| Average | 1.110 | RMS (effective) |
| RMS (effective) | 0.901 | Average |
Related Answered Questions
Question: 11.SP.7
Verified Answer:
To determine the phase angle, select a correspondi...
Question: 11.SP.8
Verified Answer:
Draw the sine waves with phase angles described. A...
Question: 11.SP.9
Verified Answer:
From Table 11-1,
V_{M} = 1.414\ V (...
Question: 11.SP.10
Verified Answer:
From Table 11-1,
I_{av} = 0.901\ I ...
Question: 11.SP.11
Verified Answer:
Use Eq. (11-9).
RMS value = 0.707 × peak value (1...
Question: 11.SP.12
Verified Answer:
Peak-to-peak amplitudes, measured between the maxi...
Question: 11.SP.13
Verified Answer:
The period T for a complete cycle is 4 μs (Fig. 11...
Question: 11.SP.15
Verified Answer:
For a parallel circuit, V_{T} = V_{1} = V_{...
Question: 11.SP.5
Verified Answer:
Write v=V_{M} \sin \theta ...
Question: 11.SP.4
Verified Answer:
If an ac wave produces as much heat as 1 A of dire...