If  ϕ=ϕ(x,y,z)=4x3ysinz,\phi=\phi(x,y,z)=4x^{3}y\,\mathrm{sin}\,z,,  find ∇Φ.

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ϕ(x,y,z)=4x3ysinz\phi(x,y,z)=4x^{3}y\sin z

so that by partial differentiation we obtain

ϕx=12x2ysinz{\frac{\partial\phi}{\partial x}}=12x^{2}y\sin z\\ ϕy=4x3sinz{\frac{\partial\phi}{\partial y}}=4x^{3}\sin z\\ ϕz=4x3ycosz{\frac{\partial\phi}{\partial z}}=4x^{3}y\cos z

Therefore

ϕ=12x2ysinzi+4x3sinzj+4x3ycoszk\nabla\phi=12x^{2}y\sin z\mathbf{i}+4x^{3}\sin z\mathbf{j}+4x^{3}y\cos z\mathbf{k}

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