Question 15.11: An equilibrium mixture of the following reaction had [I] = ......

An equilibrium mixture of the following reaction had

[ I ] = 0.075 M and [ I_2 ] = 0.88 M.

What is the value of the equilibrium constant?

I_2 (g) \xrightleftharpoons[]{} 2  I(g)

GIVEN:

[ I ] = 0.075 M

[ I_2 ] = 0.88 M

FIND: K_{eq}\\

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K_{\mathrm{eq}}={\frac{[I]^{2}}{[I_{2}]}}\\={\frac{[0.075]^{2}}{[0.88]}} \\= 0.0064

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