Question : Fig. 13.24 shows a differential gear used in a motor car. Th...

Fig. 13.24 shows a differential gear used in a motor car. The pinion A on the propeller shaft has 12 teeth and gears with the crown gear B which has 60 teeth. The shafts P and Q form the rear axles to which the road wheels are attached. If the propeller shaft rotates at 1000 r.p.m. and the road wheel attached to axle Q has a speed of 210 r.p.m. while taking a turn, find the speed of road wheel attached to axle P.

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Given : T_{ A }=12 ; T_{ B }=60 ; N_{ A }=1000 \text { r.p.m.; } N_{ Q }=N_{ D }=210 \text { r.p.m. }

Since the propeller shaft or the pinion A rotates at 1000 r.p.m., therefore speed of crown gear B,

N_{ B }=N_{ A } \times \frac{T_{ A }}{T_{ B }}=1000 \times \frac{12}{60}

= 200 r.p.m.

The table of motions is given below :

                 Revolutions of elements
Step No. Conditions of motion Gear B Gear C Gear E Gear D
1 Gear B fixed-Gear C rotated through + 1 revolution (i.e. 1 revolution anticlockwise) 0 +1 +\frac{T_{ C }}{T_{ E }} -\frac{T_{ C }}{T_{ E }} \times \frac{T_{ E }}{T_{ D }}=-1\left(\because T_{ C }=T_{ D }\right)
2 Gear B fixed-Gear C rotated through + x revolutions 0 +x +x \times \frac{T_{ C }}{T_{ E }} -x
3 Add + y revolutions to all elements +y +y +y +y
4 Total motion +y x+y y+x \times \frac{T_{ C }}{T_{ E }} y-x

Since the speed of gear B is 200 r.p.m., therefore from the fourth row of the table,

y = 200     …(i)

Also, the speed of road wheel attached to axle Q or the speed of gear D is 210 r.p.m., therefore from the fourth row of the table,

y – x = 210     or      x = y – 210 = 200 – 210 = – 10

\therefore    Speed of road wheel attached to axle P

= Speed of gear C = x + y

= – 10 + 200 = 190 r.p.m.