Question 3.58: The ΔH° rxn for abstracting each of the possible hydrogen at......

The ΔH°_{rxn} for abstracting each of the possible hydrogen atoms of propane by a bromine atom is indicated below. Based on the data and the fact that the starting materials are the same, what might be surmised about the relative energies of activation for the two reactions?
Do the transition states more closely resemble the reactants or the products?

\mathrm{CH}_{3}{\mathrm{-CH}}_{2}{\mathrm{-CH}}_{3}+\,\mathrm{Br}\quad\qquad{\mathrm{CH}}_{3}{\mathrm{-CH}}_{2}{\mathrm{-CH}}^. _{2}\ +{\mathrm{HBr}} \ \ \ \ ΔH° = +42  kJ  mole^{−1}\\ \mathrm{CH}_{3}{\mathrm{-CH}}_{2}{\mathrm{-CH}}_{3}+\mathrm{Br}\quad\quad\quad\mathrm{CH}_{3}— \dot{CH}— {\mathrm{-CH}}_{3}+\mathrm{HBr} \ \ \ \ ΔH° = +29  kJ  mole^{−1}
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The activation energy must be larger for the first reaction listed because it is the more endothermic reaction. The transition state for this reaction must more closely resemble the product than for the second reaction.

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