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Question 9.128: A cue stick strikes a stationary pool ball, with an average ......

A cue stick strikes a stationary pool ball, with an average force of 32 N over a time of 14 ms. If the ball has mass 0.20 kg, what speed does it have just after impact?

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Using the linear momentum-impulse theorem, we have

J=F_{\text{avg}}\Delta t=\Delta p=m\left(v_f-v_i\right) .

where m is the mass, v_i the initial velocity, and v_f the final velocity of the ball. With v_i =0 , we obtain

v_f=\frac{F_{\text{avg}}\Delta t}{m}=\frac{(32 \,N )\left(14 \times 10^{-3}s \right)}{0.20 \,kg}=2.24 \,m / s.

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