Question F2.18: Determine the resultant force acting on the hook....
Determine the resultant force acting on the hook.
Step-by-Step
\mathbf{F}_{1}=\left(\frac{4}{5}\right)(500 \mathrm{lb}) \mathbf{j}+\left(\frac{3}{5}\right)(500 \mathrm{lb}) \mathbf{k}
=\{400 \mathbf{j}+300 \mathbf{k}\} \mathrm{lb}
\mathbf{F}_{2}=\left[(800 \mathrm{lb}) \cos 45^{\circ}\right] \cos 30^{\circ} \mathbf{i}+\left[(800 \mathrm{lb}) \cos 45^{\circ}\right] \sin 30^{\circ} \mathbf{j}
+(800 \mathrm{lb}) \sin 45^{\circ}(-\mathbf{k})
=\{489.90 \mathbf{i}+282.84 \mathbf{j}-565.69 \mathbf{k}\} \mathrm{lb}
\mathbf{F}_{R}=\mathbf{F}_{1}+\mathbf{F}_{2}=\{490 \mathbf{i}+683 \mathbf{j}-266 \mathbf{k}\} \mathrm{lb}Related Answered Questions
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