If a 100-N force is applied to the handles of the pliers, determine the clamping force exerted on the smooth pipe B and the magnitude of the resultant force that one of the members exerts on pin A.
N_{B}=500 \mathrm{~N}
\stackrel{+}{\rightarrow} F_{x}=0 ; \quad(500 \mathrm{~N}) \sin 45^{\circ}-A_{x}=0A_{x}=353.55 \mathrm{~N}
+\uparrow \Sigma F_{y}=0 ; A_{y}-100 \mathrm{~N}-(500 \mathrm{~N}) \cos 45^{\circ}=0\begin{aligned} & A_{y}=453.55 \mathrm{~N} \\ & F_{A}=\sqrt{(353.55 \mathrm{~N})^{2}+(453.55 \mathrm{~N})^{2}} \\ &=575 \mathrm{~N} \end{aligned}