Question 1.CC.11: Canceling Units Cancel the units in the following setup and ......

All matching units in the denominator and numerator cancel to give mg as the needed unit for the answer.

3.5\,\cancel{\mathrm{L}}\times{\frac{1\times10^{3}\,\cancel{\mathrm{mL}}}{1\,\cancel{\mathrm{L}}}}\times{\frac{0.48\,\cancel{\mathrm{g}}}{1\,\cancel{\mathrm{mL}}}}\times{\frac{1\times10^{3}\,{\mathrm{mg}}}{1\,\cancel{\mathrm{g}}}}\,=\text{needed unit of mg}