The headlights of a moving car require about 10 A from the 12 V alternator, which is driven by the engine. Assume the alternator is 80% efficient (its output electrical power is 80% of its input mechanical power), and calculate the horsepower the engine must supply to run the lights.
The horsepower required is P={\frac{i V}{0.80}}={\frac{(10\,\mathrm{A})(12\ \mathrm{V})}{(0.80)(746\ \mathrm{W/hp})}}=0.20\ \mathrm{hp}.