An 18.0 W device has 9.00 V across it. How much charge goes through the device in 4.00 h?
We find the current from Eq. 26-26: i = P/V = 2.00 A. Then, from Eq. 26-1 (with constant current), we obtain
P=i V \quad \text { (rate of electrical energy transfer). } (26-26)
i=\frac{d q}{d t} \qquad \text { (definition of current). } (26-1)
\Delta q=i \Delta t=2.88 \times 10^4 \,C