A 2.0 kW heater element from a dryer has a length of 80 cm. If a 10 cm section is removed, what power is used by the now shortened element at 120 V?
Combining Eq. 26-28 with Eq. 26-16 demonstrates that the power is inversely proportional to the length (when the voltage is held constant, as in this case). Thus, a new length equal to 7/8 of its original value leads to
R=\rho \frac{L}{A}, (26-16)
P=\frac{V^2}{R} (resistive dissipation). (26-28)
P=\frac{8}{7}(2.0 \, kW )=2.4 \,kW .